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Show that the square of an odd positive ...

Show that the square of an odd positive integer is of the form `8q+1,` for some integer `qdot`

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Since any odd positive integer n is of the form `4m+1 or 4m+3.`
If `n=4m+1,` then
`n^2=(4m+1) ^2=16m^2+8m+1=8m(m+1)+1=8q+1 where q=m(m+1)`
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