m^(2)*(2)/(x)+(3)/(8)=13quad 3-y=-2

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Solve :(x+y)/(x-y)=(3)/(2),3x-2y=13

32^(2)-x^(3)=8^(3)+13^(2)

(2) (3x)/(2)-(5y)/(3)=-2 ; (x)/(3)+(y)/(2)=(13)/(6)

solve (3x)/(2)-(5y)/(3) = -2 (x)/(3)+(y)/(2) = 13/6

Solve : (x+y)^(2//3)+2(x-y)^(2//3)=3(x^2-y^2)^(1//3) and 3x-2y=13 .

(i) If the tangent at any point p(4m^(2), 8m^(3)) of x^(3) - y^(2)=0 is a normal to the curve x^(3) - y^(2) = 0 , then find the value of 9m^(2) .