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Prove that n^2-n divisible by 2 for ever...

Prove that `n^2-n` divisible by 2 for every positive integer n.

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Case i: Let `n `be an even positive integer.
When `n=2q`
In this case , we have
`n^2−n=(2q)^2 −2q=4q^2−2q=2q(2q−1)`
...
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