If `p_1a n dp_2` are two odd prime numbers such that `p_1> p_2,` then `p1 2-p2 2` is an even number (b) an odd number an odd prime number (c) a prime number

Explanation

Let the two odd prime numbers p1 and p2 be 7 and 5 respectively.


Then, `(p_1)^2=7^2=49`


and,` (p_2)^2=5^2=25`


So, `(p_1)^2−(p_2)^2=49−25=24` which is an even number.


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