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[" (2) "arcter" as: "],[qquad [(1-sin A)...

[" (2) "arcter" as: "],[qquad [(1-sin A)/(1-sec A)-(1+sin A)/(1+sec A)=2cot A(cos A-cosec A)],[" 3."]]

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(1-sin A) / (1-sec A) - (1 + sin A) / (1 + sec A) = 2cot A (cos A-cos ecA)

(1+sec A)/(sec A)=(sin^(2)A)/(1-cos A)

(1+tan A)/(sin A)+(1+cot A)/(cos A)=2(sec A+cosec A)

sin A(1+tan A)+cos A(1+cot A)=sec A+cosec A

(sin A)/(sec A+tan A-1)+(cos A)/(cos ecA+cot A-1)=1

sin A(1+tan A)+cos A(1+cot A)=sec A+cos ecA

Prove that (sec A-1)/(sec A+1)=((sin A)/(1+cos A))^(2)=(cot A-cos ecA)^(2)

sin A (1 + tan A) + cos A (1 + cot A) = sec A + cosec A .

7. (sin A+cos A)(cot A+tan A)=sec A+cosec A

(1 + sec A ) / ( sec A ) = ( sin ^ 2 A ) /( 1 - cos A )