Find the largest number that will divide 398, 436 and 542 leaving remainders 7,11 and 15 respectively.

Explanation

here, `N_1= 398-7= 391`

`N_2= 436-11 = 425`

`N_3 = 542-15 = 527`

Now,

`N_1= 391= 23*17`

`N_2= 425 = 17*5*5`

`N_3= 527= 31*17`

`HCF= 17`

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