If a perpendicular is drawn from the vertex containing the right angle of a right triangle to the hypotenuse then prove that the triangle on each side of the perpendicular are similar to each other and to the original triangle. Also, prove that the square of the perpendicular is equal to the product of the lengths of the two parts of the hypotenuse.

Explanation

Given :
Here, `ABC` is a right-angled triangle.


`∠B=90^o and BD⊥AC `



To prove :


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