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In a right triangle `A B C` right-angled at `B ,` if `P a n d Q` are points on the sides `A Ba n dA C` respectively, then (a)`A Q^2+C P^2=2(A C^2+P Q^2)` (b)`2(A Q^2+C P^2)=A C^2+P Q^2` (c)`A Q^2+C P^2=A C^2+P Q^2` (d)`A Q+C P=1/2(A C+P Q)dot`

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Verified by Experts

Applying Pythagoras theorem,
In `\triangle {AQB}`,
`A Q^{2}=A B^{2}+B Q^{2}`
In `\triangle {PBC}`
...
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