A ball is projected horizontallu from a top of tower with a velocity of `10 ms^(-1)`. Find the velocity of the ball after `0.5 s. Take ` g= 10 ms^(-2)`.

A body is projected horizontally from the top of a tower with a velocity of 30 m/s. The velocity of the body 4 seconds after projection is (g = 10ms^(-2) )

A body is projected horizontally from the top of a tower with a velocity of 30 m/s. The velocity of the body 4 seconds after projection is (g = 10ms^(-2) )

A ball is thrown horizontally from the top of a tower with a velocity of 40ms-1 .' Take g = 10 ms^2 '

A body is projected horizontally with a velocity of 4 ms^(-1) from the top of a high tower. The velocity of the body after 0.7 is nearly (Take, g = 10 ms^(-2))

A body is projected horizontally with a velocity of 4 ms^(-1) from the top of a high tower. The velocity of the body after 0.7 is nearly (Take, g = 10 ms^(-2))

From the top of a tower 100 m in height, a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 25 "m.s"^(-1) . Find when and where the two balls meet. Take g = 9.8 "m.s"^(-2) .

A ball is projected horizontally with a velocity of 4 ms^-1 .What will be its velocity after 0.7 sec (g=10 m s^-2) ?