(x-1)(x^(2)-5x+7)<(x-1)" ,then "x" belongs to "

(x^(2)-x-1)(x^(2)-x-7)<-5

Solve (x^(2)-x-1)(x^(2)-x-7)<-5

Number of integers satisfying the inequation (x^(2)-x-1)(x^(2)-x-7)<-5, are 4 (b) 2 (c) 1(d)0

If the solution of the inequality (x^(2)-x-1)(x^(2)-x-7)<-5 is x in(alpha,beta)uu(gamma,delta) then find the value of alpha+beta+gamma+delta

Simplify: x^(2)-3x+5-(1)/(2)(3x^(2)-5x+7)

If f(x)=([{x}]tan^(-1)((x^(2)-3x-1)/(x^(2)-3x-5))+3-x^(7))^(1/7) . Where [k] and {k} denotes greatest integer and fractional part functions of k respectively, then the value of f^(-1)(50)-f(50)+f(f(100)) , is

If y=tan^(-1)((1)/(x^(2)+x+1))+tan^(-1)((1)/(x^(2)+3x+3))+tan^(-1)((1)/(x^(2)+5x+7))+ to nterms,show that (dy)/(dx)=(1)/((x+n)^(2)+1)-(1)/(x^(2)+1)

If =tan^(-1)(1)/(1+x+x^(2))+tan^(-1)(1)/(x^(2)+3x+3)+tan^(-1)(1)/(x^(2)+5x+7)+ upto n terms,then find the value of y'(0) .