[" A and "B" are acute angles satisfying "],[3sin^(2)A+2sin^(2)B=1" and "3sin2A=],[2sin2B" then "cos(A+2B)=]

If AandB are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin2B=0, then A+2B is equal to (a) pi (b) (pi)/(2) (c) (pi)/(4) (d) (pi)/(6)

If A and B are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin 2B=0 , then A+2B is equal to

If A, B are acute positive angles satisfying the equations 3sin^(2)A+2sin^(2)B=1 and 3sin2A-2sin2B=0 , then find A+2B .

If A and B are acute positive angles satisfying the equations 3 sin^(2)A+2sin^(2) B=1 and 3 sin2A-2 sin 2B=0 , then A+2B is equal to

If A and B are acute angles satisfying SinA = Sin^(2) B and 2Cos^(2) A= 3Cos^(2) B then A + B =

If Aa n dB are acute positive angles satisfying the equations 3sin^2A+2sin^2B=1 and 3sin2A-2sin2B=0, then A+2B is equal to (a) pi (b) pi/2 (c) pi/4 (d) pi/6