[cos a+cos beta=a,sin a+sin beta=band],[a-beta=2 theta" then "(cos3 theta)/(cos theta)=]

If cos a+cos beta=a,sin a+sin beta=b are alpha-beta=2 theta, then (cos3 theta)/(cos3 theta)=

Ifcos alpha+cos beta=a,sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+cos beta=a*sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+cos beta=a sin alpha+sin beta=balpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+ cos beta= a, sin alpha+ sin beta= b and alpha- beta= 2 theta . Then (cos 3 theta)/(cos theta)=

If cos alpha + cos beta = a, sin alpha + sin beta = b and theta is the arithmetic mean between alpha and beta then sin 2 theta + cos 2 theta is equal to

If cos alpha + cos beta = 3/2 and sin alpha + sin beta = 1/2 and theta is the arithmetic mean of alpha and beta then sin 2 theta + cos 2 theta

If cos alpha+cos beta=(3)/(2) and sin alpha+sin beta=(1)/(2) and theta is the arithmetic mean of alpha and beta, then sin2 theta+cos2 theta is equal to: