[0.3x+0.5y=0.5],[0.5x+0.7y=0.74]

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[0.2x+0.3y=1.3],[0.4x+0.5y=2.3]

Solve for x and y: 0.4x-1.5y=6.5, 0.3x+0.2y=0.9

If 0.5x+0.7y=0.74 and 0.3x+0.5y=0.5 then

Solve the following system of equations: 0.5x+0.7y=0.74,quad 0.3x+0.5y=0.5

0.3x + 0.7y = .13 0.4x + 0.5y = .13

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The quadrilateral formed by the lines 2x-5y+7=0,5x+2y-1=0,2x-5y+2=0,5x+2y+3=0 is

If the lines 3x+2y-5=0,2x-5y+3=0,5x+by+c=0 are concurrent then b+c=