When `x, y, z` are real solve the equation `x+y=2` and `xy-z^2 = 1`

If x,y, z are real numbers satisfying the equation 25(9x^(2) + y^(2)) + 9z^(2)- 15 (5xy + yz + 3zx)= 0 then x,y, z are in

If x,y,z are real numbers such that xy=6,x-z=2 and x+y+z=9, compute (x)/(y)-(z)/(x)-(z^(2))/(xy)

If x,y,z are real numbers satisfying the equation 25(9x^2+y^2)+9z^2-15(5xy+yz+3zx)=0 then prove that x,y,z are in AP.

Using matrix method , solve the equations x-y+z=4 2x+y-3z =0 x+y+z=2

Statement -1 If x,y,z be real variables satisfying x+y+z=6 and xy+yz+z=8 , the range of variables x,y and z are identical. Statement -2 x+y+z=6 and xy+yz+zx=8 remains same if x,y,z interchange their positions.

Statement -1 If x,y,z be real variables satisfying x+y+z=6 and xy+yz+z=8 , the range of variables x,y and z are identical. Statement -2 x+y+z=6 and xy+yz+zx=8 remains same if x,y,z interchange their positions.