A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

A right circular cone is divided into two portions by a plane parallel to the base and passing through a point which is (1)/(3)rd of the height from the top.The ratio of the volume of the smaller cone to that of the remaining frustum of the cone is (a) 1: 3(b) 1: 9 (c) 1:26 (d) 1:27

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base . The ratio of the volume of the smaller cone to the whole cone is

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base.The ratio of the volume of the smaller cone to the whole cone is: 1:2 (b) 1:4 (c) 1:6 (d) 1:8

A plane divides a right circular cone into two parts of equal volume. If the plane is parallel to the base. then the ratio, in which the height of the cone is divided, is- एक तल लंब वृत्तीय शंकु को समान आयतन वाले दो भागों में विभाजित करता है। यदि तल आधार के समांतर हो, तो शंकु की ऊंचाई को किस अनुपात में,विभाजित किया जाएगा?

The height of a cone is 10cm. The cone is divided into two parts using a plane parallel to its base at the middle of its height.Find the ratio of the volumes of the two parts.

The height of a right circular cone is 20 cm. A small cone is cut off at the top by a plane parallel to the base. If its volume be 1/8 of the volume of the given cone, at what height above the base is the section made?

The volume of a right circular cone, whose radius of the base is half of its altitude, and the volume of a hemisphere are equal. The ratio of the radius of the cone to the radius of the hemisphere is: