A capacitor of capacity C charged to potential "V" and " then connected to an identical uncharged capacitor then loss of energy is

A parallel plate capacitor of capacitance C is charged to a potential V. It is then connected to another uncharged capacitor having the same capacitance. Find out the ratio of the energy stored in the combined system to that stored initially in the single capacitor.

A capacitor of capacitance C_(1) is charged to a potential difference V and then connected with an uncharged capacitor of capacitance C_(2) a resistance R. The switch is closed at t = 0. Choose the correct option(s):

A capacitor or capacitance C_(1) is charge to a potential V and then connected in parallel to an uncharged capacitor of capacitance C_(2) . The fianl potential difference across each capacitor will be

A capacitor of capacitance C_0 is charged to potential V_0 . Now it is connected to another uncharged capacitor of capacitance C_0/2 . Calculate the heat loss in this process.

A capacity of capacity C_(1) is charged up to V volt and then connected to an uncharged capacitor of capacity C_(2) . Then final potential difference across each will be

An isolated capacitor of unknown capacitance has been charged to potential V_(0) . This capacitor is then connected to an uncharged capacitor of capacity C . If common potential is V(ltV_(0) , find unknow capacitance.

An air capacitor is charged upto a potential V_1 . It is connected in parallel to an identical uncharged capacitor filled with a dielectric medium. After redistribution of charge if the potential difference of this combination is V, then the dielectric constant of the substance will be

A capacitor ' "c'" is charged to a potential "difference "V" and then it is connected to an uncharged capacitor of capacitance "'3c'." Now total loss is " ((3)/((beta-1))cv^(2)) " .The value of " beta " is "]