The angles of the depression of the top and bottom of the tower is seen from the top of a `60sqrt(3)` cliff are `45^alpha` and `60^alpha` respectively. Find the height of the tower.

Explanation

Let AD is the tower and BC is the cliff and E is the point on BC such that AD = BE

We have,

`BC = 60sqrt3, /_ CDE = 45^0 and /_BAC = 60^0 `

Let ` AD = h`

`:. AD = BE = h`

`:.CE = BC – BE = 60sqrt3 – h`


In` /_\CDE`

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