The perimeters of the ends of a frustum of a right circular cone are 44 cm and 33 cm. If the height of the frustum be 16 cm, find its volume, the slant surface and the total surface.

Explanation

Let R1 and R2 be the radius of the ends of the frustum of the cone.

So,

`2piR1 = 44 cm`

`2 x 22/7 x R1 = 44`

`R1 = 44 x 7/44`


`2piR2 = 33 cm`

`2 x 22/7 x R2 = 33`

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