A ladder makes an angle of `60^0` with the ground when placed against a wall. If the foot of the ladder is 2m away from the wall, then the length of the ladder (in metres) is

Explanation

Let AC be the ladder and AB be the wall.

Then, BC is the distance between base of the ladder & wall = 2 m.

Also, `/_C = 60^0`

Now, In `DeltaABC, cos 60^0 = (BC)/(AC)`
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` AC = (BC)/cos(60^0)=((2)/(1/2))​ = 4`m


Length of the ladder is 4 m.