A ladder rests against a wall at an angle `alpha` to the horizontal. Its foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making an angle `beta` with the horizontal. Show that

ladder rests against a wall at an angle alpha to the horizontal its foot pulled away from the wall through a distance a so that it slides a distance b down the wall making an angle beta with the horizontal.Show that (a)/(b)=(cos alpha-cos beta)/(sin beta-sin alpha)

A ladder rests against a vertical wall at angle alpha to the horizontal . If is foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making the angle beta with the horizontal , then a =

A ladder rest against a wall making an angle alpha with the horizontal.The foot of the ladder is pulled away from the wall through a distance x, so that it slides a distance y down the wall making an angle beta with the horizontal.Prove that x=y tan(alpha+beta)/(2)

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x so that it slides a distance y down the wall making an angle beta with the horizontal.The correct relation is (A) x=y tan(alpha+beta)/(2) (B) y=x tan(alpha+beta)/(2) (C) x=y tan(alpha+beta) (D) y=x tan(alpha+beta) (in)

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x so that it slides a distance y down the wall making an angle beta with the horizontal.The correct relation is (A) x=y tan(alpha+beta)/(2) (B) y=x tan(Q+beta)/(2) (c) x=y tan(alpha+beta) (0) y=x tan(alpha+beta) (a)

A ladder rests against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance ‘a’ so that it slides a distance ‘b’ down the wall making an angle beta with the horizontal then the value of (a)/(b) is

A ladder rests against a vertical wall at an angle alpha to the horizontal. If the foot is pulled away through a distance 2m, then it slides a distance 5 m down the wall, finally making an angle beta with the horizontal. The value of tan((alpha+beta)/(2)) is equal to

A ladder rests against a vertical wall at inclination alpha to the horizontal.Its foot is pulled away from the wall through a distance p so that it's upper end slides q down the wall and then ladder make an angle beta to the horizontal show that (p)/(q)=(cos beta-cos alpha)/(sin alpha-sin beta)