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Two poles are a metres apart and the height of one is double of the other. If from the middle point of the line joining their feet an observer finds the angular elevations of their tops to be complementary, then the height of the smaller is `sqrt(2)am e t r e s` (b) `1/(2sqrt(2))m e t r e s` `a/(sqrt(2))m e t r e s` (d) `2am e t r e s`

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Let AB =a be the line joining feet of the persons and C be the mid-point of this line.
Also, let h be the height of the shorter person, then height of the taller person will be 2h.
Let angle of elevations be x and 90−x as they are given complementary.
thus,
`tanx=​h/(a/2)​=(2h)/a`​....(1)
...
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