The angle of elevation of a tower from a point on the same level as the foot of the tower is `30^0dot` On advancing 150 metres towards the foot of the tower, the angle of elevation of the tower becomes `60^0dot` Show that the height of the tower is 129.9 metres (Use `sqrt(3)=1. 732` ).

Explanation

To solve the problem step by step, we will use trigonometric ratios and the information provided in the question.

### Step 1: Draw a Diagram
First, we need to visualize the problem. Draw a vertical line representing the tower (let's call the height of the tower \( H \)). Mark the point on the ground where the first observation is made as point A, and the point after advancing 150 meters towards the tower as point B.

### Step 2: Identify the Angles and Distances
From point A, the angle of elevation to the top of the tower is \( 30^\circ \). From point B, the angle of elevation is \( 60^\circ \). The distance from point A to the foot of the tower (point C) is \( D \), and the distance from point B to point C is \( D - 150 \).

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