`((1+2i)^3)/((1+i)(2-i))`

" If "z=((1+i)(1+2i)(1+3i))/((1-i)(2-i)(3-i))" then the principal argument of "z"

Simplify the following complex numbers and find their modulus. ((1+i)^(3))/((2+i)(1+2i))

Reduce ((1)/(1+2i)+(3)/(1-i))((3-2i)/(1+3i)) to the form (a + ib).

Express each of the following in the form (a + ib) and find its conjugate: {:((i),(1)/((4+3i)),(ii),(2+3i)^(2),(iii),((2-i))/((1-2i)^(2))),((iv),((1+i)(1+2i))/((1+3i)),(v),((1+2i)/(2+i))^(2),(vi),((2+i))/((3-i)(1+2i))):}

Simplify the number and find modulus . ((1 + i)^(3))/((2 + i) (1 + 2i))

Express each one of the following in the standard form a+ib:((1)/(1-2i)+(3)/(1+i))((3+4i)/(2-4i))

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Express (1 /(2 -2i)+3/(1+i)) ((3+ 4i)/(2-4i)) in the form of a +ib

Express (1 /(2 -2i)+3/(1+i)) ((3+ 4i)/(2-4i)) in the form of a +ib