A ladder 15 m long just reaches the top of a vertical wall. If the ladder makes an angle of `60^0` with the wall, then the height of the wall is (a)`15sqrt(3)m` (b) `(15sqrt(3))/2m` (c) `(15)/2m` (d) `15 m`

Explanation

Let the length of the ladder be =15m(hypotenuse)

Let the traingle be right angled at B

`/_B=90^0`

AB be the base and BC be the height



The angle between the ladder and the wall `/_BCA=60^0`


...