The straight line `x/4+y/3=1` intersects the ellipse `x^2/16+y^2/9 =1` at two points `A` and `B` such that area of `DeltaPAB` is equal to `3`, the number of such `P's` is/are

The line y=2t^2 intersects the ellipse x^2/9+y^2/4=1 in real points if :

The straight line (x)/(4)+(y)/(3) =1 intersects the ellipse (x^(2))/(16)+(y^(2))/(9) =1 at two points A and B, there is a point P on this ellipse such that the area of DeltaPAB is equal to 6(sqrt(2)-1) . Then the number of such points (P) is/are

The straight line (x)/(4)+(y)/(3) =1 intersects the ellipse (x^(2))/(16)+(y^(2))/(9) =1 at two points A and B, there is a point P on this ellipse such that the area of DeltaPAB is equal to 6(sqrt(2)-1) . Then the number of such points (P) is/are

The straight line (x)/(4)+(y)/(3)=1 intersects the ellipse (x^(2))/(16)+(y^(2))/(9)=1 at two points A and B there is a point P on this ellipse such that the area of Delta PAB is equal to 6(sqrt(2)-1) . Then the number of such point (P) is/are (A) 4 (B) 1 (C) 2 (D) 3

The straight line (x)/(4)+(y)/(3)=1 intersects the ellipse (x^(2))/(16)+(y^(2))/(9)=1 at two points A and B there is a point P on this ellipse such that the area of Delta PAB is equal to 6(sqrt(2)-1) .Then the number of such point (P) is/are

Find the area of the ellipse x^2/9 + y^2/16 = 1 .

The line y=2t^(2) intersects the ellipse (x^(2))/(9)+(y^(2))/(4)=1 in real points if

Area bounded by the ellipse : x^2/16 + y^2/9 = 1 is :

The line x=2y intersects the ellipse (x^(2))/4+y^(2)=1 at the points P and Q . The equation of the circle with PQ as diameter is