The work done in dragging a stone of mass `100 kg` up an inclined plane `1` in `100` through a distance of `10 m` is `("takeg" = 9.8 m//s^(2))`

What is the work done in dragging a stone of mass 100kg up an inclined plane 1 in 100 through a distance of 10 m?

The work done in lifting a mass of 1 kg to a height of 9.8 m is

The work done in pushing a block of mass 10 kg from bottom to the top of a frictionless inclined plane 5 m long and 3 m high is- (g=9.8m//sec^(2))

The work done in pushing a block of mass 10 kg from bottom to the top of a frictionless inclined plane 5 m long and 3 m high is- (g=9.8m//sec^(2))

Calculate work done to move a boy of mass 20 kg along an inclined plane (theta = 45^(@)) with constent velocity through a distance of 10 m.

What will be the work done by a man weighning 40 kgf and holding a body of 20 kgf on his head and moving a distance of 10 m up an incline of 10 m up an incline of 1 in 5 (Take g = 9.8 ms^(-2) ) ?

The mass of a sphereical planet is 5 times the mass of the earth, but its diameter is the same as that of the earth. How much work is done in lifting a stone of mass 3 kg through a distance of 1 m on the planet ? [g on the surface the earth = 10 m//s^(2) ]

Work done in raising 100 kg coal to 100 m height is :

The work done in sliding a wooden box of mass 5 kg along a friction less inclined plane of inclination 30^(@) and length 10 m is ______J. (g=10 m s^(-2))

The work done in pulling a body of mass 5 kg along an inclined plane (angle 60^(@) ) with coefficient of friction 0.2 through 2 m, will be -