Tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Find length of PQ

Explanation

Given,

Radius {OP}=5 {cm} and {OQ}=12 {cm}

{PQ} is the tangent to the circle.

angle O P Q`=90^{circ}`

Therefore ,by Pythagoras theorem we get,



`P Q^{2}=O Q^{2}-O P^{2} `

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