2 cubes each of volume `64" "c m^3` are joined end to end. Find the surface area of the resulting cuboid.

Explanation

The volume of cube `64 {cm}^{3}`

Side of cube `sqrt[3]{64}=4 {cm}`

Length of resulting cuboid 4+4=8

Surface area



`=2(1 b+h l+b h)`

`=2(4(4)+4(8)+8(4))`

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