If the equation `(1+m^2)x^2+2m c x+(c^2-a^2)=0` has equal roots, prove that `c^2=a^2(1+m^2)dot`

Explanation

Given:
The equation is` (1+m^{2}) x^{2}+2 m c x+c^{2}-a^{2}=0`

It need to prove `c^{2}=a^{2}(1+m^{2})`

The roots are real and equal Delta=0.

Therefore,` b^{2}-4 a c=0`


`Rightarrow(2 m c)^{2}-4(1+m^{2})(c^{2}-a^{2})=0`



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