If either `veca= vec0`or `vecb= vec0`, then ` veca * vecb = 0` But the converse need not be true. Justify your answer with an example.

Explanation

To justify the statement "If either \(\vec{a} = \vec{0}\) or \(\vec{b} = \vec{0}\), then \(\vec{a} \cdot \vec{b} = 0\), but the converse need not be true," we will follow these steps:

### Step 1: Understanding the Dot Product
The dot product of two vectors \(\vec{a}\) and \(\vec{b}\) is given by:
\[ \vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \theta \]
where \(|\vec{a}|\) and \(|\vec{b}|\) are the magnitudes of the vectors, and \(\theta\) is the angle between them.
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