The equivalent capacitance between A and B is neo A/d. Take plate area as A and separation between the plates as d. Find n. A. .B

Find the equivalent capacitance between A and B . A : area of each plate, d : separation between the plates.

Find the equivalent capacitance between A and B . A : area of each plate, d : separation between the plates.

Find out equivalent capacitance between A and B. (take each plate Area = A)

Find out equivalent capacitance between A and B. (take each plate Area = A)

Find out equivalent capacitance between A and B. (take each plate Area = A and distance between two conjugative plates is d)

Find equivalent capaciatnce of the given setup. (plate area = A, plate seperation = d)

Find the capacitances of the capacitance of the capacitors shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.

Find the charge on each plate given area of each plate is A and separation between two consecutive plates is d.

Consider a parallel plate capacitor is charged by a constant current I, with plate area A and separation between the plates d. Consider a plane surface of area A//4 parallel to the plates and drawn symmetrically between the plates. Find the displacement current through this area.