If `sin^(-1)x=y` ,then
(a) `0leylex`
(b) `(-pi)/(2)leyle(pi)/(2)`
(c) `0ltyltpi`
(d) `(-pi)/(2)ltylt(pi)/(2)`
1)c 2)d 3)a 4)b

If s in^(-1)x=y, then (A)0<=y<=pi(B)-(pi)/(2)<=y<=(pi)/(2)(C)0

sin^(-1)((-1)/2) (a) pi/3 (b) -pi/3 (c) pi/6 (d) -pi/6

sin^(-1)x+cos^(-1)x,x in[-1,1]= (A) 0 (B) (pi)/(2) (C) pi (D) 2

If (sin x)(cos y)=(1)/(2), then (d^(2)y)/(dx^(2)) at ((pi)/(4),(pi)/(4)) is (a)-4(b)-2(c)-6(d)0 at ((pi)/(4),(pi)/(4))

sin^(-1)(0) is equal to : (a) 0 (b) pi/6 (c) pi/2 (d) pi/3

sin^(-1)x+cos^(-1)x,x in[-1,1]= (A) 0 (B) (pi)/(2) (C) pi (D) 2 pi

Range of tan^(-1)((2x)/(1+x^(2))) is (a) [-(pi)/(4),(pi)/(4)] (b) (-(pi)/(2),(pi)/(2))(c)(-(pi)/(2),(pi)/(4)) (d) [(pi)/(4),(pi)/(2)]

int_(0)^( pi)(x tan x)/(sec x+cos x)dx is (pi^(2))/(4)(b)(pi^(2))/(2)(c)(3 pi^(2))/(2) (d) (pi^(2))/(3)

tan^(-1)((-1+sin1)/(cos1)) equals (A) 0(B)1-(pi)/(2) (C) (pi)/(2)-1(D)(1)/(2)-(pi)/(4)

tan^(-1)((x)/(y))-tan^(-1)((x-y)/(x+y)) is (A) (pi)/(2)(B)(pi)/(3)(C)(pi)/(4)(D)(pi)/(4) or 3(pi)/(4) is (A) (pi)/(2)(B)