A committee of 10 is to be formed from 8 teachers and 12 students of whom 4 are girls. In how many ways this can be done so that com the committee contains atleast four of either groups (teachers and students) and atleast 2 girls and atleast 2 boys are in the committee.

A committee of 11 is to be formed from 8 teachers and 12 students of whom 4 are girls. In how many ways this can be done so that the committee contains at least four of either groups (teachers and students) and at least 2 girls and atleast 2 boys are in the committee.

A committee of ten is to be formed from eight teachers and twelve students of whom four are girls. The number of committees which contains atleast four of either group (teachers and students) and atleast two girls and atleast two boys is equal to m. The number of prime factors of m is n, then (n) is equal to

A committee of 5 is to be formed from six ladies and four gentlemen . In how many ways this can be done so that the committee contains exactly two ladies ,

A committee of 5 is to be formed from six ladies and four gentlemen . In how many ways this can be done so that the committee contains at least two ladies,

A committee of 5 is to be formed from six ladies and four gentlemen . In how many ways this can be done so that the committee contains at most two ladies ?

A committee of 5 is to be formed from a group of 12 students consisting of 8 boys and 4 girls in how many ways can the committee be formed it contains at least 3 girls ?

A committee of 5 is to be formed from 6 boys and 5 girls . The number of ways that the committee can be formed so that the committee contains at least one boy and one girl is

A committee of 7 has to be formed from 9 boys and 4 girls. In how many ways can this be done when the committee consists of exactly 3 girls?

A committee of 7 has to be formed from 9 boys and 4 girls. In how many ways can this be done when the committee consists of: atmost 3 girls ?