A right triangle, whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed.

Explanation

In right angle △ABC using Pythagoras theorem


`AC=\sqrt(AB^2+BC^2) =4^2+3^2=25=5cm`


Area`(△ABC)=1/2 ×AB×AC`


`\Rightarrow 1/2×AC×OB=1/2×4×3`\Rightarrow1/2×5×OB=6`


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