[(6^(-1)-8^(-1))^(-1)=?],[(a)-(1)/(2)],[-1,-1,-1=?]

EXAMPLE 10. Simplify: (6^(-1)-8^(-1))^(-1)+(2^(-1)-3^(-1))^(-1)

Evaluate : (6^(-1)-8^(-1))^(-1)+(2^(-1)-3^(-1))^(-1)

(6^-1-8^-1)^-1+(2^-1-3^-1)^-1 =____

The inverse of the matrix A[(1,1,1),(6,7,8),(6,7,-8)] using adjoint method is ...a) -(1)/(16)[(-112,1,15),(96,-14,-2),(0,-1,1)] b) -(1)/(16)[(-112,15,1),(96,-2,-14),(0,-1,1)] c) -(1)/(16)[(-112,15,1),(96,-14,-2),(0,-1,1)] d) -(1)/(16)[(112,15,1),(96,-14,-2),(-1,0,1)]

Evaluate ((0.6)^(0)-(0.1)^(-1))/(((3)/(8))^(-1)((3)/(2))^(3)+((-1)/(3))^(-1))

Simplify : 8 (1)/(2)-[3 (1)/(4)-:{1(1)/(4) - (1)/(2) ( 1 (1)/(2)-(1)/(3)-(1)/(6))}]

If (1 + (1)/(2)) (1 + (1)/(4)) (1+(1)/(6))(1+(1)/(8))(1-(1)/(3))(1-(1)/(5)) (1-(1)/(7))=1 +(1)/(x) then what is the value of x ?

Solve 4(1)/(6)+5(1)/(6)+8(1)/(6)

If A=[[0, 1, 2], [1, 2, 3], [3, a, 1]] and A^(-1)=(-1)/(2)[[-1, 1, -1], [8, -6, -2k], [-5, 3, -1]] , then