Two water taps together can fill a tank in `9 3/8` hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

Explanation

Let the tap of the larger diameter fills the tank alone in `({x}-10) {hrs}`.

In `1 {hr}`, the tap of the smaller diameter can fill `\frac{1}{x}` part of the tank.


In `1 {hr}`, the tap of the larger diameter can fill `\frac{1}{(x-10)}` part of the tank.


Two water taps together can fill a tank in


`9 \frac{3}{8} {hrs}=\frac{75}{8} {hrs}`

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