The difference between outside and inside surface areas of cylindrical metallic pipe 14cm long is `44 c m^2dot` If the pipe is made of `99 c m^2` of metal, find the outer and inner radii of the pipe

Explanation

Let, `R` be the external radius and `r` be the inner radius of the metallic pipe. `h=` `14 {~cm}`


Outer surface area-inner surface area `=44 {~cm}^{2}`


`\therefore 2 \pi R h-2 \pi r h=44 {~cm}^{2}`


\therefore {R}-{r}=\frac{44}{2 \times \frac{22}{7} \times 14}=\frac{44 \times 7}{2 \times 22 \times 14}


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