int(ln(x+1)-ln x)/(x(x+1))dx

int(ln(x+1)-ln x)/(x(x+1))backslash dx

int(log(x+1)-log x)/(x(x+1))dx is equal to :

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c

int (log(x)-log(x+1))/(x(x+1))dx is equal to

Show that :int_(0)^(1)(log x)/((1+x))dx=-int_(0)^(1)(log(1+x))/(x)dx

Evaluate: int(log(1+1/x))/(x(1+x))dx

Evaluate: int(log(1+1/x))/(x(1+x))dx

Evaluate: int(log(1+1/x))/(x(1+x))dx

Evaluate: int(log(1+1/x))/(x(1+x))dx