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" 18."tan(x+y)+tan(x-y)=1...

" 18."tan(x+y)+tan(x-y)=1

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If tan(x+ y)tan(x-y)=1 , then the value of tan x is:

Find dy/dx : tan(x+y)+tan(x-y)=1

If tan(x+y)+tan(x-y)=1, find (dy)/(dx)

If tan(x+y)+tan(x-y)=1 , find (dy)/(dx) .

Prove that tan(x - y) + tan(y - z) + tan(z - x) = tan(x - y) *tan(y -z)* tan(z -x) .

Show that tan (x - y)+ tan (y - z) + tan (z- x) = tan (x - y) tan (y - z) tan (z- x)

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(tan(x+y)-tan x)/(1+tan(x+y)tan x)=tan y

(tan(x+y)-tan x)/(1+tan(x+y)tan x)=tan y