(tan(A+B)-tan B)/(1+tan(A+B)tan B)=tan A

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , (tan40^(@)+2tan10^(@))*(tan70^(@)-Tan20^(@))=

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , x= Tan""(5 pi)/(28)+2Tan""(pi)/(7) Then x

Prove that (tan (AB) + tan B) / (1-tan (AB) tan B) = tan A

If A+B+C=pi, prove that (tan A)/(tan B tan C)+(tan B)/(tan Atan C)+(tan C)/(tan A tan B)=tan A+tan B+tan C-2cot A-2cot B-2cot C

In a triangle ABC , right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A. Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A tan B)

In a triangle ABC ,right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A . (Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A*tan B))

tan(A+B)=(tan A+tan B)/(1-tan A tan B)

For all values of A and Btan(A+B)=(tan A+tan B)/(1-tan A tan B) and tan(A-B)=(tan A-tan B)/(1+tan A tan B)

Prove that tan(A+B+C)=(tan A+tan B+tan C-tan A tan B tan C)/(1-tan A tan B-tan B tan C-tan C tan A)

(tan A + tan B) / (tan (A + B)) + (tan A-tan B) / (tan (AB)) =