" Let "f:R-{(3)/(5)}rarr R" is defined by "f(x)=(3x+2)/(5x-3)" then "

Let f:R-{(3)/(5)}rarr R be defined by f(x)=(3x+2)/(5x-3). Then

Let f : R - (3/5) rarr R be defined by f(X) = (3x+2)/(5x-3) , then

f:R rarr R defined by f(x)=x^(2)+5

If f:R-{3/5} rarr R be defined by f(x) = (3x+2)/(5x-3) , then .........

If f" R -{3/5} to R be defined by f(x)=(3x+2)/(5x-3) , then :

Let f: R-{3/5}->R be defined by f(x)=(3x+2)/(5x-3) . Then

Let f: R-{3/5}->R be defined by f(x)=(3x+2)/(5x-3) . Then (a).f^-1(x)=f(x). (b).f-1(x)= -f(x). (c). (fof)=x (d). f-1(x)=(1/19)f(x)

If A=R-{(3)/(5)} and function f:AtoA is defined by f(x)=(3x+2)/(5x-3) , then

The function f:R rarr R is defined by f(x)=3^(-x)

Let f:R-{(5)/(4)}rarr R be a function defines f(x)=(5x)/(4x+5). The inverse of f is the map g: Range f rarr R-{(5)/(4)} given by