Steam at 100^@C is passed into 1.1 kg of...

Steam at `100^@C` is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at `15^@C`till the temperature of the calorimeter and its contents rises to `80^@C` . The mass of the steam condensed in kilogram is

0.13

0.065

0.26

0.135

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Steam at 100^(@)C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02kg at 15^(@)C till the temperature of the calorimeter and its content rises to 80^(@)C . What is the mass of steam condensed? Latent heat of steam = 536 cal//g .

A steam at 100^@C is passed into 1 kg of water contained in a calorimeter of water equivalent 0.2 kg at 9^@C till the temperature of the calorimeter and water in it is increased to 90^@C . Find the mass of steam condensed in kg(S_(w) = 1 cal//g^@C, & L_("steam") = 540 cal//g) (EAM = 14 E) .

Steam at 100^@C is passed into a calorimeter of water equivalent 10 g containing 74 cc of water and 10 g of ice at 0^@C . If the temperature of the calorimeter and its contents rises to 5^@C , calculate the amount of steam passed. Latent heat of steam =540 kcal//kg , latent heat of fusion =80 kcal//kg .

5 gm of steam at 100^@ C is passed into calorimeter containing liquid. Temperature of liquid rises from 32^@ C to 40^@ C . Then water equivalent of calorimeter and contents is

A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in beginning? Neglect heat losses. Given : Specific heat capacity of copper =0.42xx10^3 J kg^(-1) K^(-1) . Specific heat capacity of water =4.2 xx10^3 J kg^(-1) K^(-1) Specific heat of fusion of ice =3.36xx10^5 J kg^(-1) Latent heat of condensation of steam =22.5 xx 10^5 J kg^(-1)

Steam at 100^(@)C is added slowly to 1400 gm of water at 16^(@)C until the temperature of water is raised to 80^(@)C . The mass of steam required to do this is ( L_(V) = 540 cal/g)

In an experiment a sphere of aluminium of mass 0.20 kg is heated upto 150^(@) C. Immediately, it is put into water of volume 150 cc at 27^(@)C kept in a calorimeter of water equivalent to 0.025 kg. Final temperature of the system is 40^(@)C . The specific heat of aluminium is (take 4.2 Joule = 1 calorie)

A closed calorimeter of negligible water equivalent contains 1 kg of ice at 0^(@)C , the 1 kg of steam at 100^(@)C is pumped into it. Find the ratio of mass of steam to water remaining in the calorimeter after attaining equilibrium temperature. Take the efficiency of the calorimeter as 90%. Find the amount of heat lost to surroundings.

When 0.400 kg of water at 30^(@)C is mixed with 0.150 kg of water at 25^(@)C contained in a calorimeter, the final temperature is found to be 27^(@)C , find the water equivalent of the calorimeter.

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