Equal masses of air are sealed in two vessels, one of volume `V_(0)` and the other of volume `2V_(0)`. If the first vessel is maintained at a temperature `300K` and the other at `600K`, find the ratio of the pressures in the two vessels.

Explanation

As number of moles in the two vessles are equal, we have
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
It is given that `V_(1)=V_(0),V_(2)=2V_(0)` and `T_(1)=300" K",T_(2)=600" K"`
Thus we have
`(P_(1)V_(0))/(300)=(P_(2)(2V_(0)))/(600)`
or `" "P_(1)=P_(2)`
or `" "(P_(1))/(P_(2))=1`