A glass container encloses a gas a pressure of `8 xx 10^(5)` pa and 300 K temperature. The container walls can bear a maximum pressure of `10^(6)` Pa. If the temperature of container is gradually increased, find the temperature at which the container will break.

Explanation

From gas law, we have for a constant volume container
`(P_(1))/(T_(1))=(P_(2))/(T_(2))`
or `" "T_(2)=((P_(2))/(P_(1)))T_(1)`
Given that `" "P_(1)=8xx10^(5)" Pa",T_(1)=300 K,`
`P_(2)=10^(6)" Pa, then we have"`
`T_(2)=(10^(6))/(8xx10^(5))xx300=375" K"`