In a closed container of volume `10^(-3)m^(3),O_(2)` gas is filled at temperature 400 K and pressure 1.5 atm. A small hole is made in the container from which gas leaks out to pen atmosphere. After some time the temperature and pressure of container become equals to that of surrounding. Find the mass of gas that leaks out from the container. (Atmospheric temperature = 300 K)

Explanation

To solve the problem step by step, we will use the Ideal Gas Law and some basic calculations.

### Step 1: Identify the initial conditions
We have:
- Volume, \( V = 10^{-3} \, m^3 \)
- Initial temperature, \( T_1 = 400 \, K \)
- Initial pressure, \( P_1 = 1.5 \, atm \)
- Atmospheric pressure, \( P_{atm} = 1 \, atm \)
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