The lowest pressure attainable using the best available vacuum techniques is about `10^(-12) N//m^(2)`. At such a pressure, how many molecules are there per `cm^(3)` at `0^(@)C` ?

Explanation

To find the number of molecules per cubic centimeter at a pressure of \(10^{-12} \, \text{N/m}^2\) and a temperature of \(0^\circ C\), we can use the ideal gas law, which is given by the equation:

\[ PV = nRT \]

Where:
- \(P\) = pressure (in \(N/m^2\))
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