[" Wits "28+y-6=0],[4x-2y^(0)-4=0]

2x+y-6=0 , 4x-2y-4=0

2x + y - 6=0 4x - 2y - 4 = 0

The two lines 2x+y-6=0 and 4x-2y-4=0 intersect at……

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then:

Given the four lines with the equations 'x+2y-3=0,3x+4y-7=0,2x+3y-4=0,4x+5y-6=0, then

The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0

The area of the parallelogram formed by lines 2x-y+3=0, 3x+4y-6=0,2x-y+9=0, 3x+4y+4=0 is (in sq units)

Prove that the three lines 2x-y-5=0, 3x-y-6=0 and 4x-y-7=0 meet in a point.

The equation of the tangent at the point (0,3) on the circle which cuts the circles x^2 +y^2-2x+6y=0 , x^2 +y^2-4x-2y+6=0 and x^2 +y^2-12x+2y+3=0 orthogonally is