(0,0),(0,3,0)" and "(0,2)

Equation of circle passing throught (0,0),(3,0) and (0,2) is

The point equidistant from the point (0,0,0),(1,0,0,),(0,2,0) and (0,0,3) is

The point equidistant from the point (0,0,0),(1,0,0,),(0,2,0) and (0,0,3) is (A) (1/3, 2/3, 2) (B) (1,0,2) e (C) (1/2, 1, 3/20 (D) (-1, 2, 1/2)

Circumcentre of the triangle, whose vertices are (0,0), (6,0) and (0,4) is (2,0) (3,0) (0,3) (3,2)

The triangle with vertices (0,0), (2,0) and (0,3) is

Point masses 1, 2, 3 "and" 4 "kg are lying at the point (0, 0, 0), (2, 0, 0), (0, 3, 0) and (–2, –2, 0) respectively. The moment of inertia of this system about x-axis will be

If A=[(1,0),(0,3)] and B=[(2,0),(0,1)] then show AB =BA =[(2,0),(0,3)]

If A =[{:(2,0,0),(0,3,0),(0,0,5):}] , prove that, A^(2)=[{:(2^(2),0,0),(0,3^(2),0),(0,0,5^(2)):}] , hence by induction method show that, A^(n)=[{:(2^(n),0,0),(0,3^(n),0),(0,0,5^(n)):}]

Plot the following pairs of points on the axes and join them with line segment (1,0), (0,9), (2,0), (0,8), (3,0), (0,7), (4,0), (0,6) (5,0), (0,5) (6,0), (0,4) (7,0) (0,3), (8,0), (0,2), (9,0), (0,1)