A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 3.5cm and the height of the cone is 4cm. The solid is placed in a cylindrical tub, full of water, in such a way that the whole solid is submerged in water. If the radius of the cylinder is 5cm and its height is 10.5cm, find the volume of water left in the cylindrical tub. `(U s epi=(22)/7)`

Explanation

Given, `r=3.5cm` `h=4cm`

`R=5cm` `H=10.5cm`

Volume of water left in the cylinder=Volume of cylinder-(volume of cone + volume of hemisphere)
=`piR^2H-((pi/3)r^2h + 2/3pir^3)`
=`(825-(51.33+89.83)) cm^3`
(put (`pi=22/7)`)

=`683.84cm^3`