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Write the multiplicative inverse of 2-3i...

Write the multiplicative inverse of `2-3i` ?

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The correct Answer is:
Multiplicative inverse of `2-3i=1/(2-3i)xx(2+5i)/(2+3i)=(2+3i)/((2)^(2)-(3i)^(2))=(2+3i)/(4+3)=2/7+3/7i`
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